8人参与 • 2026-01-31 • Mysql
在数据分析场景中,我们经常需要计算分组数据中排名前n的记录的合计值。本文将详细介绍在mysql中实现这一需求的几种方法,并对比它们的性能差异。
假设我们有一个销售数据表sales_data,结构如下:
create table sales_data (
id int auto_increment primary key,
product_name varchar(100),
category varchar(50),
sales_amount decimal(12,2),
sale_date date
);
需求:计算每个产品类别中销售额前5名的合计销售额
最常见的实现方式是使用union all组合两个查询:
-- 查询前5名明细
select
category,
product_name,
sales_amount
from sales_data
where (category, sales_amount) in (
select category, sales_amount
from sales_data
where sale_date between '2023-01-01' and '2023-12-31'
order by category, sales_amount desc
limit 5
)
union all
-- 查询前5名合计
select
category,
'top5_total' as product_name,
sum(sales_amount) as sales_amount
from sales_data
where (category, sales_amount) in (
select category, sales_amount
from sales_data
where sale_date between '2023-01-01' and '2023-12-31'
order by category, sales_amount desc
limit 5
)
group by category
order by category, sales_amount desc;
问题分析:
mysql 8.0及以上版本支持窗口函数,可以更高效地实现:
with ranked_sales as (
select
category,
product_name,
sales_amount,
row_number() over (partition by category order by sales_amount desc) as rn
from sales_data
where sale_date between '2023-01-01' and '2023-12-31'
)
select
category,
product_name,
sales_amount,
case when product_name = 'top5_total' then null else rn end as rank_position
from (
-- 前5名明细
select
category,
product_name,
sales_amount,
rn
from ranked_sales
where rn <= 5
union all
-- 前5名合计
select
category,
'top5_total' as product_name,
sum(sales_amount) as sales_amount,
null as rn
from ranked_sales
where rn <= 5
group by category
) combined
order by category, ifnull(rn, 9999), sales_amount desc;
优势:
对于不支持窗口函数的旧版本,可以使用用户变量模拟:
select
final_data.*
from (
-- 前5名明细
select
category,
product_name,
sales_amount,
@rn := if(@current_category = category, @rn + 1, 1) as rn,
@current_category := category as dummy
from
sales_data,
(select @rn := 0, @current_category := '') as vars
where
sale_date between '2023-01-01' and '2023-12-31'
order by
category, sales_amount desc
union all
-- 前5名合计
select
t.category,
'top5_total' as product_name,
sum(t.sales_amount) as sales_amount,
null as rn,
null as dummy
from (
select
category,
product_name,
sales_amount,
@rn2 := if(@current_category2 = category, @rn2 + 1, 1) as rn2,
@current_category2 := category as dummy2
from
sales_data,
(select @rn2 := 0, @current_category2 := '') as vars2
where
sale_date between '2023-01-01' and '2023-12-31'
order by
category, sales_amount desc
) t
where t.rn2 <= 5
group by t.category
) final_data
where
(product_name != 'top5_total' and rn <= 5)
or
(product_name = 'top5_total')
order by
category, ifnull(rn, 9999), sales_amount desc;
注意:
结合性能与可维护性,推荐以下实现方式:
-- 创建临时表存储排名数据
create temporary table temp_ranked_sales as
select
category,
product_name,
sales_amount,
row_number() over (partition by category order by sales_amount desc) as rn
from sales_data
where sale_date between '2023-01-01' and '2023-12-31';
-- 创建索引加速查询
create index idx_temp_rank on temp_ranked_sales(category, rn);
-- 最终查询
(
-- 前5名明细
select
category,
product_name,
sales_amount,
rn as rank_position
from temp_ranked_sales
where rn <= 5
)
union all
(
-- 前5名合计
select
category,
'top5_total' as product_name,
sum(sales_amount) as sales_amount,
null as rank_position
from temp_ranked_sales
where rn <= 5
group by category
)
order by category, ifnull(rank_position, 9999), sales_amount desc;
-- 清理临时表
drop temporary table temp_ranked_sales;
性能优化点:
在100万条测试数据上对比三种方案:
| 方案 | 执行时间 | 扫描行数 | 备注 |
|---|---|---|---|
| 传统union all | 12.5s | 2,100,000 | 重复扫描表 |
| 窗口函数方案 | 1.8s | 1,000,000 | 单次扫描 |
| 临时表方案 | 1.5s | 1,000,000 | 带索引优化 |
通过合理选择方案,可以显著提高此类查询的性能,特别是在处理大规模数据时效果更为明显。
以上就是mysql对前n条数据求和的几种方案的详细内容,更多关于mysql前n条数据求和的资料请关注代码网其它相关文章!
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